如何使用位移和放大器将unsigned int递增1.只是逻辑上的opr? [英] How to Increment unsigned int by 1 using bit-shifting & logical opr only?

问题描述

我的作业/项目中有一个问题，仅使用 bit-shifting 和逻辑运算符将1加到无符号整数中.函数中不应包含任何"+"，-"，"*"或"/"符号.

I have a question in my assignment / project that adds 1 to an unsigned integer only using bit-shifting and logical operators. There shouldn't be any "+", "-", "*", or "/" symbols in the function.

我从最后几天开始尝试，但尚未成功.到目前为止，我已经尝试了以下方法:

I am trying from last days but no success yet. So far I've tried the following:

int A = (((B&C)<<1)^(B^C))

有人可以帮我解决这个问题吗?

Can anybody help me to solve this.?

您可以使用任何编程语言来帮助我.

You can help me in any programming language.

推荐答案

unsigned int i = ...;
unsigned int mask = 1;
while (i & mask)
{
    i &= ~mask;
    mask <<= 1;
}
i |= mask;

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