如果我使用许多“获取"资源，该如何实现资源控制器.在幼虫上? [英] How can I implement Resource Controllers if I use many "get" on the laravel?

问题描述

我有类似laravel的路线:

I have routes laravel like this :

Route::prefix('member')->middleware('auth')->group(function(){
    Route::prefix('purchase')->group(function(){
        Route::get('/', 'Member\PurchaseController@index')->name('member.purchase.index');
        Route::get('order', 'Member\PurchaseController@order')->name('member.purchase.order');
        Route::get('transaction', 'Member\PurchaseController@transaction')->name('member.purchase.transaction');
    });
});

我的控制器是这样的:

<?php
...
class PurchaseController extends Controller
{
    ...
    public function index()
    {
        ...
    }
    public function order()
    {
        ...
    }
    public function transaction()
    {
        ...
    }
}

我想将其更改为资源控制器( https://laravel.com/docs/5.6/controllers#resource-controllers )

I want to change it to Resource Controllers(https://laravel.com/docs/5.6/controllers#resource-controllers)

所以我只使用1条路线

从我的情况来看，我的路线是这样的:

From my case, my routes to be like this :

Route::prefix('member')->middleware('auth')->group(function(){
    Route::resource('purchase', 'Member\PurchaseController');
});

如果我使用resouce控制器，则只能使用index方法或show方法中的数据

If I using resouce controller, I only can data in the index method or show method

如何以订单方式和交易方式获取数据?

How can I get data in order method and transaction method?

推荐答案

您可以尝试这样，只需将资源控制器的自定义方法放在资源路由上即可.

You could try like this, Just put your resource controller custom method up resource route.

Route::prefix('member')->middleware('auth')->group(function(){
    Route::get('order', 'Member\PurchaseController@order')->name('member.purchase.order');
    Route::get('transaction', 'Member\PurchaseController@transaction')->name('member.purchase.transaction')
    Route::resource('purchase', 'Member\PurchaseController');
});

这篇关于如果我使用许多“获取"资源，该如何实现资源控制器.在幼虫上?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！