如何从Laravel中的会话数组中删除项目 [英] How to remove an item from session array in laravel

问题描述

这是我参加会议的问题

session('products')

这实际上是一个包含id的数组

this is actually an array that contains id

session('products')
array:4 [▼
0 => "1"
1 => "2"
2 => "4"
3 => "1"
]

现在我要删除，说4，我该怎么做?我尝试过方法

Now I want to delete lets say 4 How do I do that? I tried method

session()->pull($product, 'products');

但是没有用！

其他解决方案

session()->forget('products', $product);

它也不起作用

推荐答案

AFAIR必须首先检索整个数组，对其进行编辑，然后再次进行设置.如果要按产品ID删除(这是我假定的数组值)，则可以使用以下方法:

You AFAIR have to firstly retrieve whole array, edit it and then set it again. If you want to delete by product ID, which is as I assume an array value, you can use this: PHP array delete by value (not key)

$products = session()->pull('products', []); // Second argument is a default value
if(($key = array_search($idToDelete, $products)) !== false) {
    unset($products[$key]);
}
session()->put('products', $products);

---

被误解的问题

Session::pull将第一个参数作为要删除的项目，将第二个参数作为要返回的默认值.您弄错了参数的顺序.试试:

---

Misunderstood question

Session::pull takes first parameter as the item do delete and second as the default value to return. You have mistaken the order of arguments. Try:

session()->pull('products'); // You can specify second argument if you need default value

正如我在源代码中看到的，Session::forget需要字符串或数组，因此您应仅指定第一个参数:

As I can see in source, Session::forget expects string or array, so you should specify only the first parameter:

session()->forget('products');

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