Laravel刀片“旧输入或默认变量"? [英] Laravel blade "old input or default variable"?

问题描述

我想在输入值中显示旧输入.如果没有旧的输入，则显示其他变量:

I want to show the old input in input value. If there isn't old input, than show other variable:

value="{{ old('salary_' . $employee->id) or 'Default' }}"

但是当没有旧输入时，它会给我1而不是默认值！

But when there is no old input, it gives me 1 instead of the default value!

我认为问题与串联有关，但我不知道如何解决！！

I think the problem has something to do with the concatenation, but I don't know how to fix it!?

推荐答案

or是PHP中的比较运算符，因此您的代码求值为true或1. c2>语句.

or is a comparison operator in PHP, so your code is evaluating to true, or 1. What you want is a ternary if statement.

如前所述，or可以在刀片中用作三元if语句的简写.

As mentioned, or can be used in blade as shorthand for a ternary if statement.

但是您可以(并且应该)将默认值作为第二个参数传递给函数，就像这样:

But you can (and should) just pass the default value as the second argument to the function, like so:

value="{{ old('salary_' . $employee->id, 'Default') }}"

这篇关于Laravel刀片“旧输入或默认变量"?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！