检查视图是否存在，并在Laravel Blade中执行@include [英] Check if a view exists and do an @include in Laravel Blade

问题描述

使用Laravel Blade，是否有一种优雅的方法在执行@include之前检查视图是否存在?

With Laravel Blade, is there an elegant way to check if a view exists before doing an @include?

例如，我目前正在这样做:

For example I'm currently doing this:

@if(View::exists('some-view'))
    @include('some-view')
@endif

当"some-view"是一个包含变量的长字符串时，这会变得很麻烦.

Which gets quite cumbersome when 'some-view' is a long string with variables inside.

理想情况下，我正在寻找这样的东西:

Ideally I'm looking for something like this:

@includeifexists('some-view')

或者使@include仅在视图不存在时输出一个空字符串.

Or to make @include just output an empty string if the view doesn't exist.

顺便说一句，我还想提供一组视图，并使用存在的第一个视图，例如:

As an aside, I would also like to provide a set of views and the first one that exists is used, e.g.:

@includefirstthatexists(['first-view', 'second-view', 'third-view'])

如果不存在，则会输出一个空字符串.

And if none exist an empty string is output.

我将如何去做?我需要扩展BladeCompiler还是还有另一种方法?

How would I go about doing this? Would I need to extend BladeCompiler or is there another way?

推荐答案

出现了类似的问题.事实证明，从Laravel 5.3开始，有一个@includeIf刀片指令用于此目的.

Had a similar issue. Turns out that from Laravel 5.3 there is an @includeIf blade directive for this purpose.

只需执行@includeIf('some-view')

这篇关于检查视图是否存在，并在Laravel Blade中执行@include的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！