Laravel:捕获所有没有/api/段的路由 [英] Laravel: Catch all routes that does not have /api/ segment

问题描述

我需要捕获所有路由，但其中包含/api/段的路由除外. 我知道如何捕捉每条路线

I need to catch all routes, except those that have /api/ segment in them. I know how to catch every single route

Route::any('{all}', 'AngularController@serveFrontend')->where('all', '(.*)');

但是我需要更改什么，以便此字符串不捕获我的api路由?

But what do I need to change so that my api routes aren't captured by this string ?

推荐答案

您可以捕获路径不是以api

You can catch all routes where the path does not start with api

Route::any('{all}', 'AngularController@serveFrontend')->where('all', '^(?!api).*$');

或者只是将您的包包保留为最后一条路线，它将按预期运行.

Or simply leave your catchall as the last route and it'll work as expected.

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