Laravel-有没有一种方法可以将hasHas和 [英] Laravel - is there a way to combine whereHas and with

问题描述

我目前面临一个小问题.我只想在存在某些条件的关系时才返回模型.使用whereHas()方法很好用.

I'm currently facing a small problem. I want to return a model only if a relation with certain conditions exists. That's working fine with the whereHas()-method.

$m = Model
    ::whereHas(
        'programs',
        function($q) {
            $q->active();
        }
    );

但是，将关系作为这样的属性进行调用会给我全部(未过滤的结果).

However, calling the relation as a property like this will give me all (not filtered results).

$m->programs;

所以基本上我现在正在做的是:

So basically what I'm doing now is this:

$m = Model
    ::whereHas(
        'programs',
        function($q) {
            $q->active();
        }
    )
    ->with(array('programs' => function($q) {
        $q->active();
    }))
;

这很好，但是我对再次做同样的事情感到非常难过.那不是正确的方法.如何在不重复代码的情况下实现这一目标?

That's working fine but I feel very bad about doing the same thing again. That can't be the right way. How can I achieve this without kind of duplicating the code?

推荐答案

如果活动程序"的概念在您的应用程序中很重要，请考虑为活动程序创建一个单独的关系(在这种情况下，我想是有一个HasMany关系):

If a concept of an "active program" is important in your application, consider creating a separate relation just for active programs (in this case I'm presuming you have a HasMany relation):

class Model
{
    public function activePrograms()
    {
        return $this->hasMany(Program::class)->active();
    }
}

然后，您可以将查询简化为:

Then you can simplify your query to:

Model::with('activePrograms')->has('activePrograms')->get();

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