如何通过数据重定向到Laravel中的视图 [英] How to pass data through a redirect to a view in laravel

问题描述

如果我有获取路由的方法，如何在控制器执行某些操作后通过redirect()将数据从视图传递给视图?

How can I pass data from a controller after it performs certain action to a view through a redirect() if I have a get route for it?

应用程序的逻辑是使用user_id重定向到视图，在此视图中，用户将在成功验证其电子邮件后选择其用户名.

The logic of the app is to redirect with an user_id to a view where the user will select its username after successfully verified its email.

public function confirm($confirmationCode){
 if(!$confirmationCode){
   dd('No se encontró ningún código de verificación en la URL');
 }
 $user = User::where('confirmation_code', $confirmationCode)->first();
 if(!$user){
   dd('Lo sentimos. Este código de confirmación ya ha sido usado.');
 }
 $user->confirmed = 1;
 $user->confirmation_code = null;
 $user_id = $user->user_id;
 $user->save();

 return redirect('assign-username')->with(compact('user_id'));
}

获取路线:

Route::get('assign-username', 'AuthenticationController@showAssignUsernameForm');

以及assign-user表单的发帖请求代码.

And the code for the post request of the assign-user form.

public function assignUsername(){
  $user_id = request()->input('user_id');
  $username = request()->input('username');
  if(User::where('username', '=', $username)->exists()){
    return redirect()->back()->withInput()->withErrors([
    'username' => 'Este usuario ya se encuentra registrado. Intenta nuevamente'
  ]);
  }else{
    DB::table('user')->where('user_id', $user_id)->update(['username' => $username]);
  }
 }

当尝试访问$user_id变量时，它表示未定义.

When trying to access to the $user_id variable it says it is not defined.

视图的代码:

@extends('layouts.master')
@section('content')
    <section class="hero">
        <h1><span>Ya estás casi listo.</span>Es hora de seleccionar tu nombre de usuario</h1>
            <div class="form-group">
                <form class="form-group"  method="post" action="assign-username">
                    {!! csrf_field() !!}
                    @if($errors->has('username'))
                        <span class="help-block" style="color:red">
                            <strong>{{ $errors->first('username') }}</strong>
                        </span>
                    @endif
                    <input type="hidden" name="user_id" value="{{ session('user_id') }}">
                    <input type="text" name="username" placeholder="Escribe tu nombre de usuario">
                    <button type="submit" class="btn" name="send">Registrar</button>
                </form>
            </div>
        </section>
@endsection

Laravel版本:5.2

Laravel Version: 5.2

推荐答案

...

更新

在隐藏的输入上存储$user_id有点冒险，如果您的用户知道如何更改浏览器(例如Chrome开发者控制台)上的值并将其替换为另一个用户ID，怎么办?

Storing $user_id on a hidden input is a bit risky, how if your user know how to change the value on browser such as Chrome developer console and replace it with another user id?

与其将其存储在隐藏的输入中，不如将其存储为会话闪存数据，可能是:

Rather than storing it on hidden input I would store it as session flash data, it could be:

public function confirm($confirmationCode){
    ....

    session()->flash('user_id', $user_id); // Store it as flash data.

    return redirect('assign-username');
}

在AuthenticationController@showAssignUsernameForm上，告诉Laravel将您的user_id保留给下一个请求:

On AuthenticationController@showAssignUsernameForm tell Laravel to keep your user_id for next request:

public function showAssignUsernameForm() {
    session()->keep(['user_id']);
    // or
    // session()->reflash();

    return view('your-view-template');
}

在分配用户名POST的方法上，您可以定义如下值:

And on your assign username POST method you can define the value like this:

public function assignUsername(){
    $user_id  = session()->get('user_id');
    $username = request()->input('username');

    if(User::where('username', '=', $username)->exists()) {
        session()->flash('user_id', $user_id); // Store it again.

        return redirect()->back()->withInput()->withErrors([
            'username' => 'Este usuario ya se encuentra registrado. Intenta nuevamente'
        ]);
    } else {
        DB::table('user')->where('user_id', $user_id)->update(['username' => $username]);
    }
}

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