laravel 4嘲讽模拟模型关系 [英] laravel 4 mockery mock model relationships

问题描述

说我有两个从Eloquent扩展的模型，它们彼此相关.我可以嘲笑这种关系吗?

即:

class Track extends Eloquent {
    public function courses()
    {
        return $this->hasMany('Course');
    }
}

class Course extends Eloquent {
    public function track()
    {
        return $this->belongsTo('Track');
    }
}

在MyTest中，我当然想创建一个模拟，并通过调用track属性而不是track实例来返回track的实例， (我不希望查询生成器)

use \Mockery as m;

class MyTest extends TestCase {
    public function setUp()
    {
        $track = new Track(array('title' => 'foo'));
        $course = m::mock('Course[track]', array('track' => $track));

        $track = $course->track  // <-- This should return my track object
    }
}

解决方案

由于track是属性而不是方法，因此在创建模拟时，您将需要覆盖模型的setAttribute和getAttribute方法.以下是一个解决方案，可让您对要查找的属性设置期望值:

$track = new Track(array('title' => 'foo'));
$course = m::mock('Course[setAttribute,getAttribute]');
// You don't really care what's returned from setAttribute
$course->shouldReceive('setAttribute');
// But tell getAttribute to return $track whenever 'track' is passed in
$course->shouldReceive('getAttribute')->with('track')->andReturn($track);

在模拟Course对象时，无需指定track方法，除非您还想测试依赖于查询生成器的代码.如果是这种情况，那么您可以像这样模拟track方法:

// This is just a bare mock object that will return your track back
// whenever you ask for anything. Replace 'get' with whatever method 
// your code uses to access the relationship (e.g. 'first')
$relationship = m::mock();
$relationship->shouldReceive('get')->andReturn([ $track ]);

$course = m::mock('Course[track]');
$course->shouldReceive('track')->andReturn($relationship);

say I have two models that extend from Eloquent and they relate to each other. Can I mock the relationship?

ie:

class Track extends Eloquent {
    public function courses()
    {
        return $this->hasMany('Course');
    }
}

class Course extends Eloquent {
    public function track()
    {
        return $this->belongsTo('Track');
    }
}

in MyTest, I want to create a mock of course, and return an instance of track, by calling the track property, not the track instance (I don't want the query builder)

use \Mockery as m;

class MyTest extends TestCase {
    public function setUp()
    {
        $track = new Track(array('title' => 'foo'));
        $course = m::mock('Course[track]', array('track' => $track));

        $track = $course->track  // <-- This should return my track object
    }
}

解决方案

Since track is a property and not a method, when creating the mock you will need to override the setAttribute and getAttribute methods of the model. Below is a solution that will let you set up an expectation for the property you're looking for:

$track = new Track(array('title' => 'foo'));
$course = m::mock('Course[setAttribute,getAttribute]');
// You don't really care what's returned from setAttribute
$course->shouldReceive('setAttribute');
// But tell getAttribute to return $track whenever 'track' is passed in
$course->shouldReceive('getAttribute')->with('track')->andReturn($track);

You don't need to specify the track method when mocking the Course object, unless you are also wanting to test code that relies on the query builder. If this is the case, then you can mock the track method like this:

// This is just a bare mock object that will return your track back
// whenever you ask for anything. Replace 'get' with whatever method 
// your code uses to access the relationship (e.g. 'first')
$relationship = m::mock();
$relationship->shouldReceive('get')->andReturn([ $track ]);

$course = m::mock('Course[track]');
$course->shouldReceive('track')->andReturn($relationship);

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