通过最后保留null/empty对laravel集合进行排序 [英] Sorting laravel collection by leaving null/empty last

问题描述

似乎无法理解对laravel集合进行排序，因此empty/null数据最终将排在最后. (对usort有点困惑)

Can't seem to get my head around of sorting laravel collection so empty / null data would end up being last. ( bit confused about usort )

我所拥有的几乎是一堆需要订购的times/timestamps.该列可能没有某些行.

Pretty much all I have is bunch of times / timestamps that need to be ordered. Some rows may not have for that column.

我希望数据显示为ASC/ascending而最后显示empty/null数据.

I would like data to appear ASC / ascending while empty/null data is shown last.

$collection->sortBy('timestamp')排序很好，但是不知道如何处理空字段.

$collection->sortBy('timestamp') sorts nicely but doesn't know how to deal with empty fields.

表看起来像这样.

   $data = $data->sort(function($a, $b) use ($sortBy) {
        if ($a->{$sortBy} and $b->{$sortBy}) return 0; 
        return ($a->{$sortBy} > $b->{$sortBy}) ? -1 : 1;
    }); 

我在互联网上尝试过的随机代码，无法正常使用. $sortBy包含要按其排序的字段名称(因为它可能会更改) 错误的代码处理空/空数据，但顺序混乱.

Random code I tried from the internet, which I can't get to work correctly. $sortBy contains a field name to sort by ( since it may change ) Faulty code deals with empty / null data but its out of order.

推荐答案

尝试:

$collection->sortBy('-timestamp')

$collection->sortBy('-timestamp')

行得通吗?

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