PHP7构造函数类名称 [英] PHP7 Constructor class name

问题描述

我有一个Laravel 4.2应用程序，可以与PHP5一起使用，没有任何问题.由于我安装了运行PHP7的新游民箱，因此在运行模型时，如功能名称与类名称(关系功能)相同，将出现错误:

I have a Laravel 4.2 application which works with PHP5 without any problems. Since I installed a new vagrant box running PHP7 an error appears as soon as I run a model where the name of a function is the same as the class name (relationship-function) like this:

<?php

use Illuminate\Database\Eloquent\SoftDeletingTrait;

class Participant extends \Eloquent
{

    use SoftDeletingTrait;

    [...]

    public function participant()
    {
        return $this->morphTo();
    }

    [...]    

}

我收到以下错误消息:

与类同名的方法在将来的PHP版本中将不再是构造函数；参与者有一个过时的构造函数(查看:...)

Methods with the same name as their class will not be constructors in a future version of PHP; Participant has a deprecated constructor (View: ...)

所以直到今天我才知道，在PHP4中，具有相同名称的方法是类的构造函数.唔.我确实是一个糟糕的程序员.但是，在这种情况下，根据我对PHP7中发生的情况的了解，他们纠正了我的失败，因为我从不希望将此函数用作构造函数，因为它仅定义了Eloquent关系.

So what I didn't know until today is, that in PHP4 methods with the same name were the contructor of a class. Hmm. I am really a bad programmer... But in this case, from my understanding of what is happening in PHP7, they correct a failure of mine as I never wanted to use this function as a constructor, since it defines only an Eloquent relationship.

但是如何摆脱此消息?据我了解，在PHP4中我的代码有错误，但在PHP7中不是，对吧?如果不需要，我不想重构此功能，因为它已在多个地方使用.

But how can I get rid of this message? As I understand this, in PHP4 my code was buggy, but not in PHP7, right? If not necessary I do not want to refactor this function, as it is used in several places.

任何人都可以解释我做错了什么以及为什么它可以与较旧的PHP版本一起使用吗?

Can anybody explain what I am doing wrong and why it worked with older PHP versions?

谢谢！

推荐答案

据我了解，在PHP4中我的代码有错误，但在PHP7中不是，对吗?

As I understand this, in PHP4 my code was buggy, but not in PHP7, right?

不完全是. PHP4样式的构造函数仍可在PHP7上使用，它们已被弃用，并且会触发不赞成使用的警告.

Not quite. PHP4-style constructors still work on PHP7, they are just been deprecated and they will trigger a Deprecated warning.

您可以做的是定义一个__construct方法，甚至是一个空方法，这样就不会在新创建的类实例上调用php4-constructor方法.

What you can do is define a __construct method, even an empty one, so that the php4-constructor method won't be called on a newly-created instance of the class.

class foo
{
    public function __construct()
    {
        // Constructor's functionality here, if you have any.
    }

    public function foo()
    {
        // PHP4-style constructor.
        // This will NOT be invoked, unless a sub-class that extends `foo` calls it.
        // In that case, call the new-style constructor to keep compatibility.
        self::__construct();
    }
}

new foo();

它与较旧的PHP版本一起使用仅是因为构造函数没有获得返回值.每次创建Participant实例时，都隐式调用participant方法，仅此而已.

It worked with older PHP versions simply because constructors don't get return value. Every time you created a Participant instance, you implicitly call the participant method, that's all.

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