根据Laravel中的上一页重定向到其他页面 [英] Redirect to different pages based on previous page in Laravel

问题描述

想象一下，在控制器中有一个方法，例如存储一个新公司. 还要想象我们可以从站点的不同页面创建新公司.例如，我可以用2-3页创建一个公司.

Imagine you have a method in controller, like storing a new company. Also imagine we can create new company from different pages in our site. For example, I can create a company from 2-3 pages.

根据我在哪里创建公司，我需要进行不同的重定向.有时我需要重定向回去，有时需要重定向到其他路由.

Depending on where I created the company I need to have different redirects. Sometimes I need to redirect back, and sometimes to other routes.

类似:

if ($previousRoute === 'companies.index') { 
    return redirect()->back();
} else {
    return redirect()->route('someroute');
}

我想我无法获得用户来自的路线名称.如果我检查引荐来源网址，以防万一我更改路由网址，所有内容都会被破坏，因此我想依赖路由名称.另外，具有许多"if-s"或"switch"的解决方案有点奇怪，它将污染代码.

I guess I can't get the route name wher user came from. If I check referrer url then in case I change route URL everything will be broken so I want to rely on route names instead. Plus, the solution having many "if-s" or a "switch" is kind of weird, it will pollute the code.

还需要通配符支持. 带有重定向的某种路线图或类似的内容.

Also wildcard support is needed. Some kind of route map with redirects or something like this.

任何建议如何实施?

推荐答案

好吧，您可以将先前的URL与任何路由的URL进行比较.这不是最好的解决方案，我也不知道如何处理路由参数，但是它可以工作.

Well, you can compare the previous url with the url of any route. It's not the best solution and i don't know what to do with route parameters, but it can work.

if (URL::previous() === URL::route('companies.index')) { 
   return redirect()->back();
} else {
   return redirect()->route('someroute');
}

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