laravel5.2工作，如何返回数据? [英] laravel5.2 job, how to return data?

问题描述

class DataFormFields extends Job implements ShouldQueue
{
 use InteractsWithQueue, SerializesModels;

 protected $fieldList = [
        'name' => 'Tom',
        'age' => '20',
];
public function handle()
{
    $fields = $this->fieldList;

    return $fields;
}
}

控制器

public function create()
{
    $data = $this->dispatch(new DataFormFields());

    return view('create', $data);
}

我尝试dd($ data);打印0

I try to dd($data); print 0

该代码可以在laravel5.1中工作，但在5.2中则不行.帮助

the code can work in laravel5.1 ,but in 5.2 it's not ok.help

推荐答案

Laravel5.2该类将实现Illuminate\Contracts\Queue\ShouldQueue接口，从而向Laravel指示应将作业推送到队列中而不是同步运行. 所以你应该像php artisan make:job fooJob --sync

Laravel5.2 the class will implement the Illuminate\Contracts\Queue\ShouldQueue interface, indicating to Laravel that the job should be pushed onto the queue instead of run synchronously. So you should make job like php artisan make:job fooJob --sync

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