根据路线删除@include [英] Remove @include depending on the route

问题描述

我有一个菜单部分，其中包括一个输入搜索栏.但是我不希望搜索栏在所有页面上都是可见的，仅适用于两个特定的uri´s.有没有办法删除刀片中包含的内容?

I have a menu partial, that includes a input search bar. But i don't want the search bar to be visibel on all pages, only for two specific uri´s. Is there a way to remove that include in blade?

当前看起来像这样:

<a href="{{ route('all') }}">all</a>
<a href="{{ route('nes') }}">nes</a>
<a href="{{ route('snes') }}">snes</a>
@include('partials._search')

我在想类似的东西

<a href="{{ route('all') }}">all</a>
<a href="{{ route('nes') }}">nes</a>
<a href="{{ route('snes') }}">snes</a>
@if($url)
    @include('partials._search')
@endif

推荐答案

使用is()方法:

@if (request()->is($url))
    @include('partials._search')
@endif

或者，如果您知道路线名称:

Or if you know route name:

@if (request()->route()->getName() === $routeName)
    @include('partials._search')
@endif

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