Laravel查询用旧数据替换新数据 [英] Laravel query replace new data with old one

问题描述

基本上，这个问题是在 [link]

这个问题太混乱了，我想在这里分开这个问题.

As that question got too messy I want to separate the question here.

说明

我在刀片中添加了行，其中将添加几个选择框，我可以选择每个行的选项.这些数据将保存在数据库中(直到这里一切都很好)

会在我更改所选选项之一时出现，而不是进行更新，而是将所有选择都添加为新选项.

comes when I change one of my selected options and instead of being update it will add all selects as new one.

controller

public function spacssendto(Request $request) {
        $this->validate($request, array(
          'product_id' => 'required',
          'subspecifications' => 'required',
        ));

        // get all selected option
        $looped = $request->subspecifications;
        $spec = [];
        if(!empty($looped)){ //check if there is any select box without option
          foreach($looped as $sub) {
              $sub = Subspecification::find($sub);
              if (!empty($sub->id)) {
                  $data = (
                    [
                      'product_id' => $request->product_id,
                      'subspecification_id' => $sub->id,
                    ]
                  );
                  array_push($spec, $data);
              }
          }
      }
      dd($spec);
    //   DB::table('product_subspecification')->insert($spec); // save data to database
    }

屏幕截图2

dd($spec)

有什么主意吗?

推荐答案

已解决

我将函数更改为下面的代码，现在一切正常

Solved

I've changed my function to code below and now everything working fine

public function spacssendto(Request $request) {
        $this->validate($request, array(
          'product_id' => 'required',
          'subspecifications' => 'required',
        ));
        $collection = collect($request->subspecifications)->map(function ($name) {
            return strtoupper($name);
        })
        ->reject(function ($name) {
            return empty($name);
        });
      $product = Product::find($request->product_id);
      $product->subspecifications()->sync($collection);
    }

希望它可以帮助其他人.

Hope it help others.

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