Tkinter嵌套框架与网格管理器问题 [英] Tkinter Nested Frames with Grid Manager Issues

问题描述

我正在使用python 2.6及其随附的标准Tkinter重新设计接口的布局.麻烦的是，我注意到了一些奇怪的行为，并且我是Tkinter的新手，所以由于经验不足，这可能只是我所忽略的简单事情.

I am redesigning the layout for a interface using python 2.6 and the standard Tkinter included with it. Trouble is that I am noticing some strange behavior, and I am new to Tkinter so this may just be something simple I am overlooking due to inexperience.

这是一些示例代码，它们说明了如何将框架嵌套在主框架中以获得所需的布局:

Here is some example code of how I am nesting frames inside a master frame in order to get the desired layout:

import Tkinter as tk

root = tk.Tk()

master = tk.Frame(root)

frame = tk.Frame(master).grid(sticky = tk.W)

item1 = "Label One"
L1 = tk.Label(frame, text = item1).grid(sticky = tk.W)

b1 = tk.Button(frame, text = "Button 1").grid(sticky = tk.W)

find = tk.Label(frame, text = "Find").grid(sticky = tk.W)

item = tk.Entry(frame, width = 50).grid(sticky = tk.W)
##item.insert(0,"Enter Item to Search For")

L2 = tk.Label(frame, text = "Label Two").grid(sticky = tk.W)

search = tk.Button(frame, text = "Search").grid(row = 3, column = 0)

frame2 = tk.Frame(master).grid(sticky = tk.W)

list1 = tk.Listbox(frame2, width = 100).grid(sticky = tk.W)

##yscroll = tk.Scrollbar(frame2,orient = tk.VERTICAL,command = list1.yview).grid(row = 5, column = 1, sticky = tk.N + tk.S + tk.W)
yscroll = tk.Scrollbar(frame2, orient = tk.VERTICAL).grid(row = 5, column = 1, sticky = tk.N + tk.S + tk.W)
##list1.configure(yscrollcommand = yscroll.set)

##xscroll = tk.Scrollbar(frame2, orient = tk.HORIZONTAL, command = list1.xview).grid(sticky = tk.W + tk.E)
xscroll = tk.Scrollbar(frame2, orient = tk.HORIZONTAL).grid(sticky = tk.W + tk.E)
##list1.configure(xscrollcommand = xscroll.set)

root.mainloop()

当我尝试在条目小部件中插入默认值时，会发生以下错误，并且在开始嵌套框架之前它起作用:

This following error occurs when I try to insert a default value in the entry widget, and it worked before I started nesting frames:

Traceback (most recent call last):
   File "H:\Tkinter\Grid.py", line 17, in <module>
    item.insert(0,"Enter Item to Search For")
AttributeError: 'NoneType' object has no attribute 'insert'

示例代码中所有注释掉的行都会出现类似的错误.这些是我需要执行的操作，因为当前滚动条无法正常工作，因为我无法告诉他们滚动时更改列表.

Similiar errors occur on all the commented out lines in the example code.These are actions I need to perfrom because currently the scrollbars are not going to work because I can't tell them to change the list when scrolling.

1.当您像这样嵌套框架时，是否必须以其他方式访问小部件的变量?

1.When you nest frames like this do I have to access the variables of the widgets in a different manner?

2.当我使用嵌套框架，而子级和父级都使用网格时，为什么我的小部件放置仅对应于主控件的行数和列数?如果您查看Y轴滚动条的行，则必须执行master = row = 5，col = 1的操作.我相信它应该是frame2的第0行，col 1，因为该小部件的父项设置为frame2，我也希望frame2也使用网格，但是它似乎使用了主框架网格.

2.When I am using nested frames and both the children and the parent are using a grid, why would my widgets placement correspond to just the master's row and column count? If you look at the line for the Y-axis scroll bar I had to do row = 5, col = 1 of the master. I believe it should be row 0, col 1 of frame2, because the widget has the parent set as frame2 and I wanted frame2 to use a grid as well, but it seems to use the master frames grid.

3.是否可以在不同的帧中显示网格线?

3.Is it possible to display the gridlines in the different frames?

推荐答案

使用Tkinter时，您不应同时创建对象和grid.

When using Tkinter, you shouldn't create an object and grid it at the same time.

bad = tk.Button(frame).grid()  #"bad" is None since .grid returns None

good = tk.Button(frame)
good.grid()

要获取特定网格控件的信息(例如单元格)，您可能需要使用 grid_info 方法.

And to get at the information (e.g. cell) for a particular gridded widget, you probably want to use the grid_info method.

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