使用通配符的ldap查询 [英] ldap query with wildcard

问题描述

我有一个类似下面的查询

I have a query like below

(|(distinguishedName=cn=Game_BI_CHARGE_BACK,ou=Groups,ou=FC,dc=na,dc=company,dc=com)(distinguishedName=cn=Game_BI_Compliance,ou=Groups,ou=FC,dc=na,dc=company,dc=com)(distinguishedName=cn=Game_BI_Finance,ou=Groups,ou=FC,dc=na,dc=company,dc=com)(distinguishedName=cn=Game_BI_GP,ou=Groups,ou=FC,dc=na,dc=company,dc=com)(distinguishedName=cn=Game_BI_MANAGED_CARE,ou=Groups,ou=FC,dc=na,dc=company,dc=com)(distinguishedName=cn=Game_BI_MEDICAID,ou=Groups,ou=FC,dc=na,dc=company,dc=com)(distinguishedName=cn=Game_BI_PowerUser,ou=Groups,ou=FC,dc=na,dc=company,dc=com)(distinguishedName=cn=Game_BI_TRADE,ou=Groups,ou=FC,dc=na,dc=company,dc=com)(distinguishedName=cn=Game_BI_TRICARE,ou=Groups,ou=FC,dc=na,dc=company,dc=com))

我想使用通配符来缩短它，所有组名都以Game_BI开头.上面的查询有效，我只想简短一点.

I want to shorten it using wildcard, All the group names start with Game_BI. The above query works, I just want to make it short.

谢谢 沙什

推荐答案

您不能使用通配符*字符来过滤distinguishedName属性-只有完全匹配才有效.您可以在LDAP条款部分下找到有关此内容的更多信息:

You cannot use the wildcard * character to filter the distinguishedName attribute - only exact matches will work. You can read more about that here, under the LDAP Clauses section :

http://social.technet.microsoft.com/wiki/contents/articles/5392.active-directory-ldap-syntax-filters.aspx

但是，根据您当前的过滤条件，您可以按规范名称或cn进行通配符搜索，并得到相同的结果:

However, according to your current filter, you could do a wildcard search by canonical name, or cn, and get the same result :

(&(objectClass=group)(cn=Game_BI*))

也就是说，给我所有以"Game_BI"开头的规范名称的组.

That says, "Give me all the groups that have a canonical name that begins with "Game_BI".

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