如何将图例添加到具有颜色分配的散点图 [英] How to add legend to scatter plot that has colour assignment

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本文介绍了如何将图例添加到具有颜色分配的散点图的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个x和y值的列表以及每个点(绿色",蓝色",红色"等)的颜色分配列表.我发现的所有示例都基于单独的plt.scatter()命令产生了一个图例,随后的一个简单plt.legend()就足够了. 从Python熊猫中的数据帧制作matplotlib散点图.我的散点图没有每个彩色组的单独散点图.那么,如何产生一个图例来显示每个组的颜色?

I have an a list of x and y values and list of colour assignments for each point ('green', 'blue', 'red', etc). All of the examples I have found produce a legend based on separate plt.scatter() commands which later a simple plt.legend() suffices. making matplotlib scatter plots from dataframes in Python's pandas. My scatter does not have separate scatters for each coloured group. So how do I produce a legend that shows the colours of each group?

import matplotlib.pyplot as plt

colors = ["red", "orange", "green", "blue", "purple", "gray"]
regions = ["Hanoi", "Nha Trang", "Vung Tau", "Phu Quoc", "Quang Ngai", "Saigon"]
region_colors=dict(zip(regions,colors))

grp_color=[]
for i in data['Region']:
    grp_color.append(region_colors[i]) 

x_long=data[' Longitude']
y_lat=data[" Latitude"]
plt.scatter(x_long,y_lat,c=grp_color)
plt.legend(grp_color,regions,loc='right')

推荐答案

假设您有颜色列表 colors = ["blue", "red", "green"]和区域列表regions = ["Africa", "America", "Australia"] 您可以创建图例句柄列表并使用它来创建图例:

Assuming you have a list of colors colors = ["blue", "red", "green"] and a list of regions regions = ["Africa", "America", "Australia"] you can create a list of legend handles and use it to create the legend:

handlelist = [plt.plot([], marker="o", ls="", color=color)[0] for color in colors]
plt.legend(handlelist,regions,loc='right')

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