较少:根据参数生成颜色集的深色或浅色变化 [英] LESS: Generate dark or light variation of a color set based upon a parameter
问题描述
几天前,我提出了一个类似的问题,以便生成带有以下内容的LESS变量:一个LOOP
.
Some days ago I made a similar question in order to generate LESS variables with a LOOP
.
今天,我从同一个主题开始,一个相似的主题.我有以下着色剂主题:
Today I start from the same topic with a similar topic. I have the following colorizer theme:
// Colors
@color-gray: rgb(225,225,225);
@color-black: rgb(15,15,15);
@color-blue: rgb(37,117,237);
@color-red: rgb(222,44,59);
@color-yellow: rgb(255,200,0);
@color-green: rgb(44,159,66);
@color-white: rgb(255,255,255);
// Colors Dark
@color-gray-dark: rgb(179,182,183);
@color-black-dark: rgb(0,0,0);
@color-blue-dark: rgb(26,82,165);
@color-red-dark: rgb(178,35,47);
@color-yellow-dark: rgb(204,160,0);
@color-green-dark: rgb(35,127,53);
// Colors Light
@color-gray-light: rgb(240,240,240);
@color-black-light: rgb(55,55,55);
@color-blue-light: rgb(146,186,246);
@color-red-light: rgb(239,150,157);
@color-yellow-light: rgb(255,228,128);
@color-green-light: rgb(150,207,161);
最大七个阶段已经回答了我:
无法动态生成"变量
There's no way to "generate" variables dynamically
那么,如何优化类似着色剂的创建?如果有可能生成变量,理想的行为应将深色"或浅色"参数传递给循环遍历每个标准"颜色变化的函数,然后自动生成深色或浅色版本.
So, how to optimize creation of a similar colorizer? If could be possible to generate variables, ideal behaviour should pass a "dark" or "light" parameter to a function that loops through each "standard" color variation and then generates dark or light version automatically.
对此有何建议?
推荐答案
我不确定我是否完全理解您的问题,但是不久前,我不得不面对一个类似的问题,并通过使用LESS mixins作为函数来解决了这个问题,并根据主要颜色(例如背景色)确定要使用的变体(浅色或深色).
I'm not sure if I fully understand your question, but not long ago I had to face a similar issue and solved it by using LESS mixins as functions, and based on a main color (e.g. background color), deciding which variant to use (light or dark).
例如
@mainColor: #F4F8F8;
.generate(@color) when (lightness(@color) >= 50%) {
// 'Color variables here'
}
.generate(@color) when (lightness(@color) < 50%) {
// 'Color variables here'
}
.generate(@mainColor);
不确定它是否满足您的需求.
Not sure if it meets what you are looking for.
干杯.
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