使用libcurl使https获取 [英] Making https get with libcurl

问题描述

我正在尝试连接到Google API.
这在我的终端中正常运行，我正在这样做:
curl https://www.googleapis.com/tasks/v1/users/@me/lists --header "Authorization: Bearer myAccessCode".
效果很好，但现在我想在c程序中制作它.
为此，我有:

I'm trying to connect to a google api.
This works fine in my terminal, there I'm doing:
curl https://www.googleapis.com/tasks/v1/users/@me/lists --header "Authorization: Bearer myAccessCode".
This works fine, but now I want to make this inside a c program.
For this I have:

    CURL *curl;
    char *header = "Authorization:  Bearer myAccessCode";
    struct curl_slist *headers = NULL;
    headers = curl_slist_append(headers, header);

    curl = curl_easy_init();

    char *response = NULL;

    curl_easy_setopt(curl, CURLOPT_URL, "https://www.googleapis.com/tasks/v1/users/@me/lists");
    curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headers);
    curl_easy_setopt(curl, CURLOPT_HTTPGET, 1);

    curl_easy_setopt(curl, CURLOPT_SSL_VERIFYPEER, 0L);
    curl_easy_setopt(curl, CURLOPT_SSL_VERIFYHOST, 0L);

    curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headers);
    curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, httpsCallback);
    curl_easy_setopt(curl, CURLOPT_WRITEDATA, &response);

    curl_easy_perform(curl);
    curl_easy_cleanup(curl);

但是在这里，我只是收到一条消息，要求登录. 我不知道我在做什么错，有人看到我的失败吗?

But here I'm just getting a message that a login is required. I have no idea what I'm doing wrong, is there someone who sees my failure?

推荐答案

就像我在上面的评论中所写的那样:
我刚刚意识到自己做了:curl_slist_append(headers, header);
代替:headers = curl_slist_append(headers, header);
所以标头始终为NULL，我没有标头就发出了get请求.
(我在上面的问题中对其进行了编辑，因此该代码可以运行，如果有的话)

Like I wrote in the comment above:
I just realized that I made: curl_slist_append(headers, header);
instead of: headers = curl_slist_append(headers, header);
So headers was always NULL and I made the get request without a header.
(I edited it in my question above, so the code works, if some)

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