片段可以在提升中获取参数吗? [英] Can snippets take parameters in lift?

问题描述

lift是否有办法将参数传递给摘要?

Is there a way in lift to pass parameters to snippets?

我正在尝试为我的页面编写一个 pluraize 过滤器，该过滤器将显示单词"user"或"users"，具体取决于数量:

I am trying to write a pluraize filter for my page that will display the word "user" or "users" depending on how many there are:

1 user
2 users

它在Django中的工作方式称为过滤器，它们的编写方式如下:

The way it works in Django is called filters and they are written as follows:

You have {{ num_messages }} message{{ num_messages|pluralize }}.

所以在这里您可以看到 pluralize 函数采用整数 num_messages 并输出和适当的字符串-空的"或"s".

So here you can see pluralize function takes an integer num_messages and outputs and appropriate string - either empty "" or "s".

请注意，在这种情况下， num_messages 是一个实际的上下文变量，从视图传递到模板.

Note that the num_messages in this case is an actual context variable, passed down to the template from the view.

推荐答案

您可以将参数传递给代码片段，是的.

You can pass parameters to snippets, yes.

class MySnippet {
  def foo: NodeSeq = {
    x = S.attr("myparam") openOr "myparam: Y U NO DEFINED!?"
    <p>I got {x}!</p>
  }
}

使用:

<lift:MySnippet.foo myparam="3"/>

或者，较新的Lift 2.3+样式:

Or, newer Lift 2.3+ style:

<div class="lift:MySnippet.foo?myparam=3"/>

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