JavaFX行填充颜色 [英] JavaFX line fill color

问题描述

我正在尝试创建一条具有不同填充和描边颜色的线，如下所示:

I'm trying to create a line with a different fill and stroke color, something like this:

我尝试了以下操作:

Line line = new Line(0,0,100,100);
line.setFill(Color.RED);
line.setStroke(Color.BLACK);
line.setStrokeWidth(10);

但这给了我一条黑线.

but this gives me just a black line.

我想用一条简单的Line做什么还是我必须使用另一个Shape? (我宁愿使用一行，因为我必须经常调用setStartX，setStartY，...方法)

Is what I'm trying to do possible with a simple Line or do I have to use another Shape? (I would prefer using a line because I have to frequently call the setStartX, setStartY, ... methods)

推荐答案

如果选中此

If you check this question, you'll see that you can only use setStroke. Also, a possible approach to generate the same styling is proposed by using a linear gradiant.

这将起作用(在您方便的时候停下来调整或多或少的黑色宽度):

This will work (adjust stops at your convenience for more or less black width):

Line line = new Line(0,0,100,0);
line.setStrokeWidth(10);
line.setStroke(new LinearGradient(0d, -5d, 0d, 5d, false,
                CycleMethod.NO_CYCLE, new Stop(0,Color.BLACK), 
                                      new Stop(0.199,Color.BLACK),
                                      new Stop(0.2,Color.RED),
                                      new Stop(0.799,Color.RED),
                                      new Stop(0.8,Color.BLACK)));

还要注意，由于梯度不成比例，因此需要使用旋转来生成非水平线.

Note also that since the gradient is not proportional, you need to use rotation to generate not horizontal lines.

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