JSON解析结果的Andr​​oid [英] Parsing JSON Result Android

问题描述

我建立了JSON格式接收的一些数据的Andr​​oid应用程序。目前的结果非常难看。我想在我的应用程序的多个TextViews整齐地显示此数据，但我不知道如何去做。下面来源$ C ​​$ C。

Main.java

 进口java.io.IOException异常;
进口的java.io.InputStream;进口org.apache.http.HttpEntity;
进口org.apache.http.Htt presponse;
进口org.apache.http.client.HttpClient;
进口org.apache.http.client.methods.HttpGet;
进口org.apache.http.impl.client.DefaultHttpClient;
进口org.apache.http.protocol.BasicHttpContext;
进口org.apache.http.protocol.HttpContext;进口android.app.Activity;
进口android.os.AsyncTask;
进口android.os.Bundle;
进口android.view.View;
进口android.view.View.OnClickListener;
进口android.widget.Button;
进口android.widget.TextView;公共类主要活动扩展实现OnClickListener {    TextView的TXT1;
    @覆盖
    公共无效的onCreate（捆绑savedInstanceState）{
        super.onCreate（savedInstanceState）;
        的setContentView（R.layout.main）;
        findViewById（R.id.my_button）.setOnClickListener（本）;
    }    @覆盖
    公共无效的onClick（查看为arg0）{
        按钮B =（按钮）findViewById（R.id.my_button）;
        b.setClickable（假）;
        新LongRunningGetIO（）执行（）;
    }    私有类LongRunningGetIO扩展的AsyncTask＆LT;太虚，太虚，字符串＆GT; {        保护字符串getASCIIContentFromEntity（HttpEntity实体）抛出IllegalStateException异常，IOException异常{
           InputStream的时间= entity.getContent（）;
             StringBuffer的出=新的StringBuffer（）;
             INT N = 1;
             而（N 0）{
                 字节[] B =新的字节[4096];
                 N = in.read（B）;
                 如果（N 0）out.append（新字符串（B，0，N））;
             }
             返回out.toString（）;
        }        @覆盖
        保护字符串doInBackground（虚空...... PARAMS）{
             HttpClient的HttpClient的=新DefaultHttpClient（）;
             HttpContext的localContext =新BasicHttpContext（）;
             HTTPGET HTTPGET =新HTTPGET（https://api.myjson.com/bins/363s3）;
             字符串文本= NULL;
             尝试{
                   HTT presponse响应= httpClient.execute（HTTPGET，localContext）;
                   HttpEntity实体= response.getEntity（）;
                   文字= getASCIIContentFromEntity（实体）;
             }赶上（例外五）{
                 返回e.getLocalizedMessage（）;
             }
             返回文本;
        }        保护无效onPostExecute（字符串结果）{
            如果（结果！= NULL）{
                TXT1 =（的TextView）findViewById（R.id.textView1）;
                txt1.setText（结果）;
            }
            按钮B =（按钮）findViewById（R.id.my_button）;
            b.setClickable（真）;
        }
    }
}
 

解决方案

怎么样努力类似，

 的JSONObject的JSONObject =新的JSONObject（jsonString）;
 

顺便说一句，排球是任何一种请求好的库。

I am building an Android application that receives some data in JSON format. At the moment the result is very ugly. I want to display this data neatly in multiple TextViews in my application but I am not to sure how to do it. Source code below.

Main.java

import java.io.IOException;
import java.io.InputStream;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.protocol.BasicHttpContext;
import org.apache.http.protocol.HttpContext;

import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.TextView;

public class Main extends Activity implements OnClickListener {

    TextView txt1;
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        findViewById(R.id.my_button).setOnClickListener(this);
    }

    @Override
    public void onClick(View arg0) {
        Button b = (Button)findViewById(R.id.my_button);
        b.setClickable(false);
        new LongRunningGetIO().execute();
    }

    private class LongRunningGetIO extends AsyncTask <Void, Void, String> {

        protected String getASCIIContentFromEntity(HttpEntity entity) throws IllegalStateException, IOException {
           InputStream in = entity.getContent();
             StringBuffer out = new StringBuffer();
             int n = 1;
             while (n>0) {
                 byte[] b = new byte[4096];
                 n =  in.read(b);
                 if (n>0) out.append(new String(b, 0, n));
             }
             return out.toString();
        }

        @Override
        protected String doInBackground(Void... params) {
             HttpClient httpClient = new DefaultHttpClient();
             HttpContext localContext = new BasicHttpContext();
             HttpGet httpGet = new HttpGet("https://api.myjson.com/bins/363s3");
             String text = null;
             try {
                   HttpResponse response = httpClient.execute(httpGet, localContext);
                   HttpEntity entity = response.getEntity();
                   text = getASCIIContentFromEntity(entity);
             } catch (Exception e) {
                 return e.getLocalizedMessage();
             }
             return text;
        }   

        protected void onPostExecute(String results) {
            if (results!=null) {
                txt1 = (TextView)findViewById(R.id.textView1);
                txt1.setText(results);
            }
            Button b = (Button)findViewById(R.id.my_button);
            b.setClickable(true);
        }
    }
}

解决方案

What about trying something like,

JSONObject jsonObject = new JSONObject(jsonString);

By the way, Volley is a good library for any kind of requests.

这篇关于JSON解析结果的Andr​​oid的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！