在Ruby中规范行尾 [英] Normalizing line endings in Ruby

问题描述

我在Ruby中有一个字符串，s(例如)，该字符串可能具有任何标准行结尾(\n，\r\n，\r).我想将所有这些都转换为\n.最好的方法是什么?

I have a string in Ruby, s (say) which might have any of the standard line endings (\n, \r\n, \r). I want to convert all of those to \ns. What's the best way?

这似乎是一个非常常见的问题，但是关于它的文档并不多.显然有简单的粗略解决方案，但是有内置的东西可以解决这个问题吗?

This seems like a super-common problem, but there's not much documentation about it. Obviously there are easy crude solutions, but is there anything built in to handle this?

优雅，惯用的Ruby解决方案是最好的.

意识到^M和\r是相同的.但是仍然有三种情况. (请参见维基百科.)

realized that ^M and \r are the same. But there are still three cases. (See wikipedia.)

推荐答案

最好只是处理您要专门更改的两种情况，而不要变得太聪明:

Best is just to handle the two cases that you want to change specifically and not try to get too clever:

s.gsub /\r\n?/, "\n"

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