GSON自定义分析 [英] GSON Custom parsing

问题描述

您好我正在写与输出JSON格式信息的外部Web服务接口的Andr​​oid应用程序。

Hi I'm writing an android App that interfaces with an external webservice that outputs JSON formatted info.

我使用GSON生成Web服务输出的POJO，但我有这个实体的问题：

I'm using GSON to generate POJOs for the output of the web service, but I'm having a problem with this entity:

player: {
 1: {
   number: "6",
   name: "Joleon Lescott",
   pos: "D",
   id: "2873"
 },
 2: {
   number: "11",
   name: "Chris Brunt",
   pos: "D",
   id: "15512"
 },
 3: {
   number: "23",
   name: "Gareth McAuley",
   pos: "D",
   id: "15703"
 }
}

使用如 http://www.jsonschema2pojo.org/ 服务，我能够产生一个POJO符合这个输出是这样的：

Using a service like http://www.jsonschema2pojo.org/ I was able to generate a POJO that matches to this output like this:

public class Player {

   @SerializedName("1")
   @Expose
   private com.example._1 _1;
   @SerializedName("2")
   @Expose
   private com.example._2 _2; 
   .....
}

public class _1 {

 @Expose
 private String name;
 @Expose
 private String minute;
 @Expose
 private String owngoal;
 @Expose
 private String penalty;
 @Expose
 private String id;
 ....
}

不过，我想这个调整一点点，而不是具有_1的对象，_2，等等，我想有一个包含所有数据的数组或列表，像这样：

However I would like to tweak this a little bit and instead of having an object for _1, _2, etc, I would like to have an array or list containing all data, like this:

public class Players{

   private List<Player> players;

}

public class Player{
   @Expose
   private int position;
   @Expose
   private String name;
   @Expose
   private String minute;
   @Expose
   private String owngoal;
   @Expose
   private String penalty;
   @Expose
   private String id;
   ....
}

我怎么能做到这一点，无需手动解析JSON文件？

How can I accomplish this, without manually parsing the JSON file?

推荐答案

注册一个 TypeAdapter 您播放类。在反序列化方法遍历键在 JSON ，并将它们添加到的ArrayList 。这应该工作，我想。在伪code的例子：

Register a TypeAdapter for your Players class. In the deserialize method iterate over keys in the json and add them to an ArrayList. That should work, I think. An example in pseudo-code:

class PlayersAdapter implements JsonDeserializer<Players> {
    public Players deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext ctx) {
        List<Player> players = new ArrayList<>();
        for (Map.Entry<String, JsonElement> entry : json.getAsJsonObject().entrySet()) {
            players.add(ctx.deserialize(entry.getValue(), Players.class));
        }
        return new Players(players);
    }
}


// ...
Gson gson = new GsonBuilder()
        .registerTypeAdapter(Players.class, new PlayersAdapter())
        .create();

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