展平一个列表,其属性之一是另一个对象列表 [英] Flatten a list which one of its properties is another list of object
本文介绍了展平一个列表,其属性之一是另一个对象列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有以下课程:
public class Owner
{
public string Id { get; set; }
public string Name { get; set; }
}
public class Main
{
public string Id { get; set; }
public string Name { get; set; }
public List<Owner> Owners { get; set; }
}
我想将List<Main>
转换为FlatList所在的List<FlatList>
I want to convert List<Main>
to List<FlatList>
where FlatList is
public class FlatList
{
public string Id { get; set; } // Id from Main
public string Name { get; set; } // Name from Main
public string OwnerId { get; set; } // Id from each Owner in a Main's Owner
public string OwnerName { get; set; } // Name from each Owner in a Main's Owner
}
不幸的是,我无法找出LinQ查询来执行此操作.
Unfortunately I haven't been able to figure out the LinQ query to perform this operation.
推荐答案
You should use SelectMany to flatten a sequence of Main objects:
将序列的每个元素投影到IEnumerable并展平 产生的序列变成一个序列.
Projects each element of a sequence to an IEnumerable and flattens the resulting sequences into one sequence.
因此它将每个Main对象投影到FlatList
个对象的序列中,然后将得到的序列展平为一个FlatList
个序列
So it projects each Main object into sequence of FlatList
objects and then flattens resulting sequences into one FlatList
sequence
var flatList = mainList.SelectMany(m =>
m.Owners.Select(o =>
new FlatList {
Id = m.Id,
Name = m.Name,
OwnerId = o.Id,
OwnerName = o.Name
})).ToList()
这篇关于展平一个列表,其属性之一是另一个对象列表的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文