安卓：从FFT到音符得到映射频率 [英] Android : Mapping frequency obtained from FFT to musical notes

问题描述

开发它映射的乐器弹奏的音符的应用程序。例如： - 如果C是钢琴演奏，应用程序显示一个C

Developing an application which maps the note played on an instrument. Example:- If a C is played on the piano, the application displays a C.

double [] notes={16.35,17.32,18.35,19.45,20.6,21.83,23.12,24.5,25.96,27.5,29.14,30.87};
        char [] notations={'c','C','d','D','e','f','F','g','G','a','A','b'};
        int index=0;
        double minvalue=999999;
        if(values[0]>16.34){
        for (int i=0;i<=11;i++)
        {
            double result=values[0]%notes[i];
            if(result==0)
            {
                index=i;
                break;
            }
            double temp=notes[i]-result;
            if(temp<minvalue)
            {
                minvalue=temp;
                index=i;
            }
        }
        TextView display2 = (TextView) findViewById(R.id.textView2);
        display2.setText(String.valueOf(notations[index]));

笔记阵列由十二个不同的音符的频率。
值[0]由其中获得的频率。
值[0]％笔记[i]的用于确定频率属于最接近音符

notes array consists of the frequencies of the twelve different notes. value[0] consists of the frequency which is obtained. value[0]%notes[i] is used to determine the closest note the frequency belongs to.

问题：

中的值发生很大的变化！
由于其中，当C是在钢琴上演奏，它集在C，但qucikly其他一些不是因为改变值的变化。

The values change a lot! Because of which, when C is played on the piano, It sets on C, but changes qucikly to some other not because of the changing values.

有没有更好的映射方案可以遵循？

Is there a better mapping scheme which can be followed?

推荐答案

您应该寻找基音检测算法

真实世界的声音是不是静态的。每个泛音的相对强度可以在不同的速率随时间而改变。在给定时刻，声音的基本频率可以从FFT峰值幅度不同。

Real-world sounds are not static. Relative intensity of each overtone may change at different rate over time. The fundamental frequency of a sound at given moment can be different from FFT peak magnitude.

P.S。发现多个COM prehensive答案

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