如何在LINQ中查询此XML? [英] How to query this XML in LINQ?
本文介绍了如何在LINQ中查询此XML?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我很难使用XML中的属性和嵌套元素.
如果我只想提取具有属性Type="Mobile"
的Phone
元素并在一行中打印地址,该如何在LINQ中执行此操作?
I find it hard using attributes and nested elements in XML.
How should I do this in LINQ if I want to extract only the Phone
element with the attribute Type="Mobile"
and print the address in one line?
我想产生这样的输出:
332-899-5678 | 123 Main, St Mercer Island, WA 68042
请帮助,以下是我的示例XML文件
Please help, below is my sample xml file
<Contacts>
<Contact>
<Name>Patrick Hines</Name>
<Phone Type="Home">206-555-0144</Phone>
<Phone Type="Work">425-555-0145</Phone>
<Phone Type="Mobile">332-899-5678</Phone>
<Address>
<Street1>123 Main St</Street1>
<City>Mercer Island</City>
<State>WA</State>
<Postal>68042</Postal>
</Address>
</Contact>
</Contacts>
推荐答案
string xml = @"<Contacts>
<Contact>
<Name>Patrick Hines</Name>
<Phone Type=""Home"">206-555-0144</Phone>
<Phone Type=""Work"">425-555-0145</Phone>
<Phone Type=""Mobile"">332-899-5678</Phone>
<Address>
<Street1>123 Main St</Street1>
<City>Mercer Island</City>
<State>WA</State>
<Postal>68042</Postal>
</Address>
</Contact>
<Contact>
<Name>Dorothy Lee</Name>
<Phone Type=""Home"">910-555-1212</Phone>
<Phone Type=""Work"">336-555-0123</Phone>
<Phone Type=""Mobile"">336-555-0005</Phone>
<Address>
<Street1>16 Friar Duck Ln</Street1>
<City>Greensboro</City>
<State>NC</State>
<Postal>27410</Postal>
</Address>
</Contact>
</Contacts>";
XDocument document = XDocument.Parse(xml);
var query = from contact in document.Descendants("Contact")
let address = contact.Element("Address")
select new
{
Name = contact.Element("Name").Value,
MobilePhone = contact.Elements("Phone").Where(ele => ele.Attribute("Type").Value == "Mobile").First().Value,
Street1 = address.Element("Street1").Value,
City = address.Element("City").Value,
State = address.Element("State").Value,
Postal = address.Element("Postal").Value
};
foreach (var item in query)
{
Console.WriteLine("{0} | {1}, {2}, {3} {4}", item.MobilePhone, item.Street1, item.City, item.State, item.Postal);
}
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