LINQ在List< List< string>>中获得唯一计数/排序. [英] LINQ to get Distinct Count/Sort in List<List<string>>

问题描述

我有一个包含List<string>的List<>，我需要根据List<string确定唯一计数，并按计数频率进行排序.

I have a List<> that contains a List<string>, of which I need to determine the unique count from the List<string, and order by the frequency of the count.

示例:

• "a"，"b"，"c"
• "d"，"e"，"f"
• "a"，"b"
• "a"，"b"，"c"
• "a"，"b"，"c"
• "a"，"b"

这将输出(等级/组合/频率)

This would output (rank / combination / frequency)

• 1-"a"，"b"，"c"-3
• 2-"a"，"b"-2
• 3个"d"，"e"，"f"-1

我可以提出一种蛮力方法，但是使用LINQ可以更优雅地做到这一点吗?据我所知，这完全不是笛卡尔方法.

I can come up with a brute-force approach but can this be done more elegantly with LINQ? This isn't exactly a Cartesian approach from what I can tell.

谢谢.

推荐答案

您可以编写自己的IEqualityComparer并将其与GroupBy一起使用.

You could write your own IEqualityComparer and use it with GroupBy.

public class StringArrayValueComparer : IEqualityComparer<List<string>>
{
    public bool Equals(List<string> x, List<string> y)
        => x.SequenceEqual(y);

    public int GetHashCode(List<string> obj)
        => obj.Aggregate(1, (current, s) => current * 31 + s.GetHashCode());
}

var list = new List<List<string>>(new[]
{
    new List<string>(new [] { "a", "b", "c" }),
    new List<string>(new [] { "d", "e", "f" }),
    new List<string>(new [] { "a", "b" }),
    new List<string>(new [] { "a", "b", "c" }),
    new List<string>(new [] { "a", "b", "c" }),
    new List<string>(new [] { "a", "b" })
});

var orderedList = list
    .GroupBy(x => x, x => x, (x, enumerable) => new { Key = x, Count = enumerable.Count()}, new StringArrayValueComparer())
    .OrderByDescending(x => x.Count)
    .Select((x, index) => new { Rank = index + 1, Combination = x.Key, Frequency = x.Count });

foreach (var entry in orderedList)
{
    Console.WriteLine($"{entry.Rank} - {string.Join(",", entry.Combination)} - {entry.Frequency}");
}

1-a，b，c-3

1 - a,b,c - 3

2-a，b-2

3-d，e，f-1

3 - d,e,f - 1

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