根据时间戳C#的XML删除节点 [英] XML delete node according to timestamp C#

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本文介绍了根据时间戳C#的XML删除节点的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我需要有关如何基于时间戳自动"删除节点的帮助.特定日期由用户在xml文档中定义,例如2006年9月17日 有人可以给我一个例子吗? 预先感谢!

I need help on how to "automatically" delete a node based on timestamp. A particular date is defined by the user inside a xml document e.g. 17/9/2006 Can someone provide me an example? Thanks in advance!

   <root>
    <element>
    </element>
    <timestamp time="2016-09-16T13:45:30">
    </timestamp>
    <--how do I delete element based on the given timestamp?-->
    </root>

  //UNTESTED CODE

     XDocument doc = XDocument.Load("time.xml");
     var name = doc.Descendants("root")
        .Where(n => n.Attribute("time").Value == "2016-09-16T13:45:30")
        .Select(n => (string)n) 
        .First(); 
      <--how can I delete it based on timestamp-->
         name.Element("element").Remove();

推荐答案

假设您要与DateTime变量inputDate进行比较.

Lets suppose you want to compare with a DateTime variable inputDate.

// I have formatted yor XML and structured it. "root" is the the parent node. Elements are the child elements of root consisting of timestamp tag.

 string xmlInput =  @"
 <root>
 <element>
 <timestamp time='2016-09-16T13:45:30'>
 </timestamp>
 </element>
 <element>
 <timestamp time='2016-10-16T13:45:30'>
 </timestamp>
 </element>
 </root>";

    XDocument  xdoc = XDocument.Parse(xmlInput);
    xdoc.Descendants("root").Elements("element").
                             Where(x => DateTime.Compare(DateTime.Parse(x.Element("timestamp").Attribute("time").Value,null, DateTimeStyles.RoundtripKind).Date, inputDate.Date) ==0).
                             ToList().ForEach(x => x.Remove());

我已经将每个元素的xml日期timestampinputdate进行了比较,以仅等于日期而不是时间.您可以满足任何条件.

I have compared the xml date timestamp for each element with inputdate for equality of only Date not the time. You can have any condition you want.

注意:您需要使用System.Globalization进行引用;

Note: You need to refer using System.Globalization;

using System.Globalization;
using System.Xml.Linq;
using System.Xml;
using System.Linq;

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