使用linq返回带有list< object>的对象.成员 [英] Using linq to return an object with a list<object> member

问题描述

我对Linq to SQL还是有些陌生.我正在寻找一种通过使用单个linq查询来获取对象的所有成员的方法.我遇到的问题是，类成员之一是自定义对象的列表.它是这样的:

I am still somewhat new to Linq to SQL. I am looking for a way to get all members of an object by using a single linq query. The problem I haev run into is that one of the class members is a list of custom objects. It goes something like this:

班级:

public class RoomConfiguration
{
    public int ConfigID {get;set;}
    public string ConfigName { get; set; }
    public int RowCount { get; set; }
    public int ColCount { get; set; }
    public int FillDirection { get; set; }
    public string BigDoor { get; set; }
    public string SmallDoor { get; set; }
    public List<LineConfig> Lines { get; set; }
}

我正在寻找一个linq查询，它将填充该类的所有成员，包括Lines. Lines的数据来自另一个表，我也为其定义了一个类.

I am looking for a linq query that will fill in all of the members of this class, including Lines. The data for Lines comes from another table which I have defined a class for as well.

感谢任何对此有解决方案的人.非常感谢您的帮助！

Thank you to anyone who may have a solution for this. Help is much appreciated!

推荐答案

有点困难，不知道您的表如何关联，但是您可以这样做:

It's a little hard, not knowing how your tables relate, but you could do this:

var configs = db.RoomConfigurations
                .Select( r => new RoomConfiguration
                 {
                     ConfigID = r.ConfigID,
                     ConfigName = r.ConfigName,
                     ...
                     Lines = db.LineConfigs
                               .Where( l => l.RoomConfigID == r.ConfigID )
                               .ToList()
                 });

或

var configs = db.RoomConfigurations
                .Join( db.LineConfigs, r => r.ConfigID, l => l.RoomConfigID, (r,l) => new { RoomConfig = r, LineConfigs = l } )
                .GroupBy( j => j.RoomConfig )
                .Select( g => new RoomConfiguration
                 {
                     ConfigID = g.Key.ConfigID,
                     ConfigName = g.Key.ConfigName,
                     ...
                     Lines = g.LineConfigs.ToList()
                 });

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