如何在Linux上使用grep仅显示文件名? [英] How can I use grep to show just filenames on Linux?

问题描述

如何在Linux上使用grep仅显示文件名(无内联匹配)?

How can I use grep to show just file-names (no in-line matches) on Linux?

我通常使用类似的东西:

I am usually using something like:

find . -iname "*php" -exec grep -H myString {} \;

如何仅获取文件名(带有路径)，而没有匹配项?我必须使用xargs吗?在我的grep手册页上没有找到执行此操作的方法.

How can I just get the file-names (with paths), but without the matches? Do I have to use xargs? I didn't see a way to do this on my grep man page.

推荐答案

标准选项grep -l(小写的L)可以做到这一点.

The standard option grep -l (that is a lowercase L) could do this.

从 Unix标准:

-l
    (The letter ell.) Write only the names of files containing selected
    lines to standard output. Pathnames are written once per file searched.
    If the standard input is searched, a pathname of (standard input) will
    be written, in the POSIX locale. In other locales, standard input may be
    replaced by something more appropriate in those locales.

在这种情况下，您也不需要-H.

You also do not need -H in this case.

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