递归计数Linux目录中的文件 [英] Recursively counting files in a Linux directory

问题描述

如何递归计算Linux目录中的文件?

How can I recursively count files in a Linux directory?

我发现了:

find DIR_NAME -type f ¦ wc -l

但是当我运行它时，它会返回以下错误.

But when I run this it returns the following error.

查找:路径必须在表达式之前:

find: paths must precede expression: ¦

推荐答案

这应该有效:

find DIR_NAME -type f | wc -l

说明:

• -type f仅包含文件.
• |(而非¦ )将find命令的标准输出重定向到wc命令的标准输入.
• wc(单词计数的缩写)对输入的换行符，单词和字节进行计数(文档).
• -l仅计算换行符.

• -type f to include only files.
• | (and not ¦) redirects find command's standard output to wc command's standard input.
• wc (short for word count) counts newlines, words and bytes on its input (docs).
• -l to count just newlines.

注释:

• 用.替换DIR_NAME以在当前文件夹中执行命令.
• 您还可以删除-type f以在计数中包括目录(和符号链接).
• 如果文件名可以包含换行符，则此命令可能会计数过多.

• Replace DIR_NAME with . to execute the command in the current folder.
• You can also remove the -type f to include directories (and symlinks) in the count.
• It's possible this command will overcount if filenames can contain newline characters.

说明您的示例无效的原因:

在显示的命令中，您没有使用管道"(|)来连接两个命令，而是使用了断线(¦)，shell无法将其识别为命令或其他内容.相似的.这就是为什么您收到该错误消息的原因.

In the command you showed, you do not use the "Pipe" (|) to kind-of connect two commands, but the broken bar (¦) which the shell does not recognize as a command or something similar. That's why you get that error message.

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