Linux脚本，用于检查进程是否正在运行并根据结果采取行动 [英] Linux Script to check if process is running and act on the result

问题描述

我的流程经常失败&有时会启动重复的实例..

I have a process that fails regularly & sometimes starts duplicate instances..

当我跑步时: ps x |grep -v grep |grep -c "processname" 我会得到: 2 这是正常现象，因为该过程与恢复过程一起运行.

When I run: ps x |grep -v grep |grep -c "processname" I will get: 2 This is normal as the process runs with a recovery process..

如果我知道 0 我将要开始这个过程 如果我有: 4 我将要停止&重新启动过程

If I get 0 I will want to start the process if I get: 4 I will want to stop & restart the process

我需要一种获取ps x |grep -v grep |grep -c "processname"

然后设置一个简单的3选项功能

Then setup a simple 3 option function

ps x |grep -v grep |grep -c "processname"
if answer = 0 (start process & write NOK & Time to log /var/processlog/check)
if answer = 2 (Do nothing & write OK & time to log /var/processlog/check)
if answer = 4 (stot & restart the process & write NOK & Time to log /var/processlog/check)

此过程停止 killall -9 process 该过程开始于 process -b -c /usr/local/etc

The process is stopped with killall -9 process The process is started with process -b -c /usr/local/etc

我的主要问题是找到一种对ps x |grep -v grep |grep -c "processname"的结果采取行动的方法.

My main problem is finding a way to act on the result of ps x |grep -v grep |grep -c "processname".

理想情况下，我想使grep的结果成为脚本中的变量，如下所示:

Ideally, I would like to make the result of that grep a variable within the script with something like this:

process=$(ps x |grep -v grep |grep -c "processname")

如果可能的话.

推荐答案

用于监视系统上的进程是否正在运行的程序.

脚本存储在crontab中，每分钟运行一次.

Script is stored in crontab and runs once every minute.

#! /bin/bash

case "$(pidof amadeus.x86 | wc -w)" in

0)  echo "Restarting Amadeus:     $(date)" >> /var/log/amadeus.txt
    /etc/amadeus/amadeus.x86 &
    ;;
1)  # all ok
    ;;
*)  echo "Removed double Amadeus: $(date)" >> /var/log/amadeus.txt
    kill $(pidof amadeus.x86 | awk '{print $1}')
    ;;
esac

0如果找不到进程，请重新启动它.
1如果找到了进程，则一切正常.
*如果进程运行2个或更多，则杀死最后一个.

0 If process is not found, restart it.
1 If process is found, all ok.
* If process running 2 or more, kill the last.

它只是测试pidof程序中的退出标志$?.将会是0进程正在运行，如果不是1.

It just tests the exit flag $? from the pidof program. It will be 0 of process is running and 1 if not.

#!/bin/bash
pidof  amadeus.x86 >/dev/null
if [[ $? -ne 0 ]] ; then
        echo "Restarting Amadeus:     $(date)" >> /var/log/amadeus.txt
        /etc/amadeus/amadeus.x86 &
fi

---

最后是一支班轮

pidof amadeus.x86 >/dev/null ; [[ $? -ne 0 ]] && echo "Restarting Amadeus:     $(date)" >> /var/log/amadeus.txt && /etc/amadeus/amadeus.x86 &

cccam oscam

cccam oscam

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