当使用锁定文件来避免脚本的两个实例同时运行时，如何避免竞争状况? [英] How to avoid race condition when using a lock-file to avoid two instances of a script running simultaneously?

问题描述

避免同一脚本的两个实例同时运行的典型方法如下:

A typical approach to avoid two instances of the same script running simultaneously looks like this:

[ -f ".lock" ] && exit 1
touch .lock
# do something
rm .lock

是否有更好的方法来锁定shell脚本中的文件，从而避免出现竞争状况?必须使用目录吗?

Is there a better way to lock on files from a shell-script, avoiding a race condition? Must directories be used instead?

推荐答案

是的，示例脚本中确实存在竞争条件.您可以使用bash的noclobber选项来在比赛中失败，而-f测试和touch之间会出现一个不同的脚本.

Yes, there is indeed a race condition in the sample script. You can use bash's noclobber option in order to get a failure in case of a race, when a different script sneaks in between the -f test and the touch.

以下是示例代码段(受这篇文章的启发)说明了该机制:

The following is a sample code-snippet (inspired by this article) that illustrates the mechanism:

if (set -o noclobber; echo "$$" > "$lockfile") 2> /dev/null; 
then
   # This will cause the lock-file to be deleted in case of a
   # premature exit.
   trap 'rm -f "$lockfile"; exit $?' INT TERM EXIT

   # Critical Section: Here you'd place the code/commands you want
   # to be protected (i.e., not run in multiple processes at once).

   rm -f "$lockfile"
   trap - INT TERM EXIT
else
   echo "Failed to acquire lock-file: $lockfile." 
   echo "Held by process $(cat $lockfile)."
fi

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