如何从UTF-8文件中删除BOM表? [英] How can I remove the BOM from a UTF-8 file?
问题描述
我有一个使用BOM表以UTF-8编码的文件,并且想要删除BOM表.是否有任何Linux命令行工具可从文件中删除BOM表?
I have a file in UTF-8 encoding with BOM and want to remove the BOM. Are there any linux command-line tools to remove the BOM from the file?
$ file test.xml
test.xml: XML 1.0 document, UTF-8 Unicode (with BOM) text, with very long lines
推荐答案
BOM是Unicode代码点U + FEFF; UTF-8编码由三个十六进制值0xEF,0xBB,0xBF组成.
A BOM is Unicode codepoint U+FEFF; the UTF-8 encoding consists of the three hex values 0xEF, 0xBB, 0xBF.
使用bash,您可以使用$''
特殊引用格式创建UTF-8 BOM,该格式实现Unicode转义:$'\uFEFF'
.因此,使用bash,从文本文件开头删除UTF-8 BOM的可靠方法是:
With bash, you can create a UTF-8 BOM with the $''
special quoting form, which implements Unicode escapes: $'\uFEFF'
. So with bash, a reliable way of removing a UTF-8 BOM from the beginning of a text file would be:
sed -i $'1s/^\uFEFF//' file.txt
如果文件不是以UTF-8 BOM开始,则文件将保持不变,否则将删除BOM.
This will leave the file unchanged if it does not start with a UTF-8 BOM, and otherwise remove the BOM.
如果您使用其他外壳程序,您可能会发现"$(printf '\ufeff')"
生成BOM字符(与zsh
以及任何不带内置printf
的外壳程序一起使用,前提是/usr/bin/printf
是Gnu版本),但是如果您想要兼容Posix的版本,则可以使用:
If you are using some other shell, you might find that "$(printf '\ufeff')"
produces the BOM character (that works with zsh
as well as any shell without a printf
builtin, provided that /usr/bin/printf
is the Gnu version ), but if you want a Posix-compatible version you could use:
sed "$(printf '1s/^\357\273\277//)" file.txt
(-i
就地编辑标记也是Gnu扩展;此版本将可能已修改的文件写入stdout.)
(The -i
in-place edit flag is also a Gnu extension; this version writes the possibly-modified file to stdout.)
这篇关于如何从UTF-8文件中删除BOM表?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!