遍历ls -l输出的每一行 [英] Iterating over each line of ls -l output

问题描述

我要遍历输出ls -l /some/dir/*

现在我正在尝试:for x in $(ls -l $1); do echo $x; done

但是，这会分别遍历行中的每个元素，所以我得到:

However, this iterates over each element in the line separately, so I get:

-r--r-----
1
ivanevf
eng
1074
Apr
22
13:07
File1

-r--r-----
1
ivanevf
eng
1074
Apr
22
13:17
File2

但是，我想遍历整个行.我该怎么办?

But I want to iterate over each line as a whole, though. How do I do that?

推荐答案

将IFS设置为换行符，如下所示:

Set IFS to newline, like this:

IFS='
'
for x in `ls -l $1`; do echo $x; done

如果您不想永久设置IFS，请在其周围放置一个子外壳:

Put a sub-shell around it if you don't want to set IFS permanently:

(IFS='
'
for x in `ls -l $1`; do echo $x; done)

或在|时使用改为阅读:

Or use while | read instead:

ls -l $1 | while read x; do echo $x; done

另一个选项，它在同一shell级别上运行while/read:

One more option, which runs the while/read at the same shell level:

while read x; do echo $x; done << EOF
$(ls -l $1)
EOF

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