使用awk计算一列中单词出现的次数 [英] Using awk to count the number of occurrences of a word in a column

问题描述

03/03/2014 12:31:21 BLOCK 10.1.34.1 11:22:33:44:55:66

03/03/2014 12:31:22 ALLOW 10.1.34.2 AA:BB:CC:DD:EE:FF

03/03/2014 12:31:25 BLOCK 10.1.34.1 55:66:77:88:99:AA

我正在尝试使用awk来在一个命令中计算上面单词"block"和"access"的出现次数.

I am trying to use awk to count the number of occurrences of the word "block" and "access" above in one command.

我最初尝试使用阻止"一词，但我的计数器似乎无法正常工作.谁能看到我的代码在哪里错误?

I tried the word "block" at first but my counter does not appear to be working. Can anyone see where my code is wrong?

awk ' BEGIN {count=0;}  { if ($3 == "BLOCK") count+=1} end {print $count}' firewall.log

推荐答案

使用数组

awk '{count[$3]++} END {for (word in count) print word, count[word]}' file

如果要专门阻止":END {print count["BLOCK"]}

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