如何在C中屏蔽密码? [英] How to mask password in c?

问题描述

在C语言中，我想显示用户键入的每个单个字符* (例如，请输入您的密码:*****)

In C, I want to display every single character that the user type as * (Ex, Please type in your password: *****)

我正在四处搜寻，但无法为此找到解决方案. 我正在使用Ubuntu.有人知道一个好方法吗?

I'm searching around but can't be able to find a solution for this. I'm working on Ubuntu. Does anybody know a good way?

推荐答案

请参阅我的代码.它可以在我的FC9 x86_64系统上运行:

See my code. it works on my FC9 x86_64 system:

#include <stdio.h>
#include <string.h>
#include <unistd.h>
#include <termios.h>

int main(int argc, char **argv)
{
        char passwd[16];
        char *in = passwd;
        struct termios  tty_orig;
        char c;
        tcgetattr( STDIN_FILENO, &tty_orig );
        struct termios  tty_work = tty_orig;

        puts("Please input password:");
        tty_work.c_lflag &= ~( ECHO | ICANON );  // | ISIG );
        tty_work.c_cc[ VMIN ]  = 1;
        tty_work.c_cc[ VTIME ] = 0;
        tcsetattr( STDIN_FILENO, TCSAFLUSH, &tty_work );

        while (1) {
                if (read(STDIN_FILENO, &c, sizeof c) > 0) {
                        if ('\n' == c) {
                                break;
                        }
                        *in++ = c;
                        write(STDOUT_FILENO, "*", 1);
                }
        }

        tcsetattr( STDIN_FILENO, TCSAFLUSH, &tty_orig );

        *in = '\0';
        fputc('\n', stdout);

        // if you want to see the result: 
        // printf("Got password: %s\n", passwd);

        return 0;
}

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