如何在C ++中使用cin隐藏用户输入? [英] How do I hide user input with cin in C++?

问题描述

可能重复:
从std :: cin

Possible Duplicate:
Read a password from std::cin

我正在尝试制作一个简单的密码程序，以使我熟悉C ++，但是我遇到了一些问题.在此代码中，我要求用户输入他们选择的密码，然后他们输入该密码.我要编写的代码是隐藏输入(不用* s代替)，但是仍然显示光标以及输入密码之前，之后的文本，例如:

I'm trying to make a simple password program so I can get familiar with C++, but I'm having a bit of a problem. In this code, I ask the user for a password they choose, and then they enter it. What I want to code to do is hide the input (not replace it with *s), but still show the cursor, and the text above, before, and after the password is entered, like this:

Please enter password: [don't show input]
Please re-enter password: [don't show input]

我该怎么做?我正在使用Linux，因此将无法使用任何Windows库(windows.h等).

How can I do this? I'm using Linux, so I won't be able to use any windows libraries (windows.h, etc).

推荐答案

您不能直接使用cin执行此操作.您必须降低".尝试调用以下功能:

You cannot do this directly using cin. You have to go "lower". Try calling these functions:

#include <termios.h>

...

void HideStdinKeystrokes()
{
    termios tty;

    tcgetattr(STDIN_FILENO, &tty);

    /* we want to disable echo */
    tty.c_lflag &= ~ECHO;

    tcsetattr(STDIN_FILENO, TCSANOW, &tty);
}

void ShowStdinKeystrokes()
{
   termios tty;

    tcgetattr(STDIN_FILENO, &tty);

    /* we want to reenable echo */
    tty.c_lflag |= ECHO;

    tcsetattr(STDIN_FILENO, TCSANOW, &tty);
}

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