如何从失败的命令返回退出代码0 [英] How to return exit code 0 from a failed command

问题描述

我想从失败的命令返回退出代码"0".有没有比这更简单的方法了?

I would like to return exit code "0" from a failed command. Is there any easier way of doing this, rather than:

function a() {
  ls aaaaa 2>&1;
}

if ! $(a); then
  return 0
else
  return 5
fi

推荐答案

只需将return 0附加到函数以强制函数始终成功退出.

Simply append return 0 to the function to force a function to always exit successful.

function a() {
  ls aaaaa 2>&1
  return 0
}

a
echo $? # prints 0

如果出于任何原因希望内联，可以将|| true附加到命令:

If you wish to do it inline for any reason you can append || true to the command:

ls aaaaa 2>&1 || true
echo $? # prints 0

如果要反转退出状态，只需在命令前加上!

If you wish to invert the exit status simple prepend the command with !

! ls aaaaa 2>&1
echo $? # prints 0

! ls /etc/resolv.conf 2>&1
echo $? # prints 1

此外，如果您说出要实现的总体目标，我们也许可以指导您获得更好的答案.

Also if you state what you are trying to achieve overall we might be able to guide you to better answers.

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