为什么" [1> 2]";评估为True? [英] Why "[ 1 > 2 ]" evaluates to True?
问题描述
我有两个文件:
f1.txt:
I have two files:
f1.txt:
1
dest/f1.txt:
dest/f1.txt:
1
2
当我在linux终端上的两个文件上都运行wc -l
时,我得到了预期的结果:
When I run wc -l
on both of those files in linux terminal - I get my expected results:
$ wc -l < f1.txt
$ 1
$ wc -l < dest/f1.txt
$ 2
但是当我运行以下.sh文件时:
But when I run the following .sh file:
#!/bin/bash
if [ $(wc -l < f1.txt) > $(wc -l < dest/f1.txt) ]; then
echo -e "f1 has more lines"
else
echo -e "f1 doesn't have more lines"
fi
输出为:
f1 has more lines
您能解释一下这怎么可能吗?
Can you explian how could this be possible?
推荐答案
您应该在if
子句中使用-gt
进行整数比较.
You should use the -gt
for integer comparison in a if
clause.
如果使用>
或<
,您将最终进行 ASCII字母顺序比较.
If you use >
or <
you will end up doing ASCII alphabetic order comparison.
整数比较
-eq
等于
if [ "$a" -eq "$b" ]
-ne
不等于
if [ "$a" -ne "$b" ]
-gt
大于
if [ "$a" -gt "$b" ]
-ge
大于或等于
if [ "$a" -ge "$b" ]
-lt
小于
if [ "$a" -lt "$b" ]
-le
小于或等于
if [ "$a" -le "$b" ]
<
小于(在双括号内)
(("$a" < "$b"))
<=
小于或等于(在双括号内)
(("$a" <= "$b"))
>
大于(在双括号内)
(("$a" > "$b"))
>=
大于或等于(在双括号内)
(("$a" >= "$b"))
字符串比较
=
等于
if [ "$a" = "$b" ]
警告
请注意=
的空白框架.
Caution
Note the whitespace framing the =
.
if [ "$a"="$b" ] is not equivalent to the above.
==
等于
if [ "$a" == "$b" ]
这是=
的同义词.
Note
The == comparison operator behaves differently within a double-brackets test than within single brackets.
[[ $a == z* ]] # True if $a starts with an "z" (pattern matching).
[[ $a == "z*" ]] # True if $a is equal to z* (literal matching).
[ $a == z* ] # File globbing and word splitting take place.
[ "$a" == "z*" ] # True if $a is equal to z* (literal matching).
!=
不等于
if [ "$a" != "$b" ]
此运算符在[[ ... ]]
构造中使用模式匹配.
This operator uses pattern matching within a [[ ... ]]
construct.
<
小于,按ASCII字母顺序
<
is less than, in ASCII alphabetical order
if [[ "$a" < "$b" ]]
if [ "$a" \< "$b" ]
请注意,"<"
需要在[ ]
构造中转义.
Note that the "<"
needs to be escaped within a [ ]
construct.
>
大于,按ASCII字母顺序
>
is greater than, in ASCII alphabetical order
if [[ "$a" > "$b" ]]
if [ "$a" \> "$b" ]
Note that the ">" needs to be escaped within a [ ] construct.
-z
字符串为空,即长度为零
-z
string is null, that is, has zero length
String='' # Zero-length ("null") string variable.
if [ -z "$String" ]
then
echo "\$String is null."
else
echo "\$String is NOT null."
fi # $String is null.
-n
string is not null.
来源: http://tldp.org/LDP/abs/html /comparison-ops.html
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