如何从Linux脚本中的路径中删除结束文件夹名称? [英] How to remove end folder name from a path in Linux script?

问题描述

我试图在Linux中创建一个简单的命令，类似于DOS中的cd...我试图做的是制作一个脚本，该脚本通过删除最后一个文件夹名称来将目录更改为必须从pwd获取的路径.

I am trying to make a simple command in Linux similar to cd.. in DOS. What I tried is to make a script that changes directory to a path, which I have to get from pwd, by removing the last folder name.

对于路径:/home/usr/Downloads/images我想获取/home/usr/Downloads.

推荐答案

您可以使用dirname命令来执行所需的操作，它会删除文件中的最后一个部分".如果您提供的是目录，则将获得父目录.

You can use the dirname command to do what you're asking for, it remove the last "part" from a file. If what you give it is a directory, you'll get the parent directory.

parent=$(dirname /your/path/here)

但是用脚本执行cd..是不可能的-cd仅会影响运行脚本的外壳，而不会影响调用脚本的外壳.

But doing a cd.. with a script is not possible - the cd would only affect the shell that the script is running in, not the shell that invoked the script.

因此，您必须使用别名或函数.

So you have to use an alias or a function.

alias cd..='cd ..'

或

cdp() {
  cd ..
}

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