如何确定文件在* nix上是否为只读文件? [英] How can I determine if a file is read-only for my process on *nix?

问题描述

使用stat函数，我可以获得以下内容的读/写权限:

Using the stat function, I can get the read/write permissions for:

• 所有者
• 用户
• 其他

...但这不是我想要的.我想知道文件对我的进程(即我正在编写的应用程序)的读/写权限.仅当我知道我的进程是否以文件的所有者/用户/其他身份运行时，所有者/用户/其他才有帮助...所以也许这是解决方案，但我不确定到达那里的步骤.

...but this isn't what I want. I want to know the read/write permissions of a file for my process (i.e. the application I'm writing). The owner/user/other is only helpful if I know if my process is running as the owner/user/other of the file...so maybe that's the solution but I'm not sure of the steps to get there.

推荐答案

您不想为此使用stat().您要使用<unistd.h>中的access():

You don't want to use stat() for this. You want to use access() from <unistd.h>:

char const* name = "file";
if (access(name, R_OK)) {
    std::cout << "'" << name << "' is readable\n";
}
if (access(name, W_OK)) {
    std::cout << "'" << name << "' is writable\n";
}

这篇关于如何确定文件在* nix上是否为只读文件?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！