Linux nasm程序集打印从零到100的所有数字 [英] linux nasm assembly print all numbers from zero to 100

问题描述

我正在编写一个程序，以打印出从零到100的所有数字.我这样做的唯一原因是测试打印出多个数字.

I am writing a program to print out all the numbers from zero to 100. The only reason I am doing this is to test out printing out multiple digit numbers.

我遇到的问题是我的程序只打印出数字1和2.我不知道为什么.我的编译器可以正常编译，没有错误，也没有链接器错误.

The problem that I am having is that my program is only printing out the numbers 1 and 2. I have no idea why. My compiler compiles fine, without error, as well as no linker errors.

这是我的代码:

SECTION .data
len EQU 32
NUL EQU 0
countlen EQU 8

SECTION .bss
counter resb countlen
strlen resb countlen

SECTION .text
GLOBAL _start
_start:
    mov BYTE[counter], 1              ; set counter to 1
    mov BYTE[strlen], 1               ; set string length counter to 1
    mov ecx, counter                  ; move the counter to ecx
    add BYTE[ecx], NUL                ; add null terminator to ecx
    mov esi, 9                        ; move 9 to esi

Length: 
    cmp [counter], esi                ; compare counter to esi
    jle Set                           ; if equal, goto set
    inc BYTE[strlen]                  ; increment the string size
    mov eax, 10                       ; move 10 to eax
    mov ebx, esi                      ; move esi to ebx
    mul ebx                           ; multiply ebx by esi
    add eax, 9                        ; add nine to the result
    mov esi, eax                      ; move the result to esi
    jmp Length                        ; jump to Length 

Set:
    mov esi, 9                        ; reset checker

Check:
    cmp BYTE[strlen], 1               ; is it one digit?
    je Single                         ; if yes, jump to single
    cmp BYTE[strlen], 3               ; is it 100?
    je Exit                           ; if yes, jump to Exit

Print:                                 ; this section deals with multi-digit numbers                                   
    cmp BYTE[ecx], NUL                ; check if end of string
    je Exit                           ; if equal goto exit 
    mov eax, 4
    mov ebx, 1
    mov edx, 1
    int 80h                           ; print number

    inc ecx                           ; point to next digit in number
    jmp Print                         ; jump to Print

Single:                                   ; this section deals with single digit numbers         add BYTE[counter], '0'            ; convert to ASCII
    mov eax, 4                       
    mov ebx, 1
    mov ecx, counter 
    mov edx, countlen 
    int 80h                           ; print the digit
    jmp Length                        ; go back

Exit:                                     ; Exit section
    mov eax, 1                        ; sys_exit
    mov ebx, 0                        ; return 0
    int 80h                           ; syscall

为什么要这样做?另外，我需要进行哪些更改才能使其按预期工作?

Why does it do this? Also, what do I need to change to get it to work as expected?

预先感谢

RileyH

更新:

经过编辑以包含打印"标签

Edited to include the 'Print' label

推荐答案

这是我在stdout上打印数字的功能.在AT& T抱歉；)

This is my function to print the digits on stdout. It's in AT&T sorry ;)

movl <your decimal here>, %eax
xor %ecx, %ecx  # the counter
movl $10, %ebx  

loop:
xor %edx, %edx
div %ebx        # isolate the last digit, remainder in edx
add $48, %dx    # '0' is 48 in ascii, result is the ascii equivalent
shl $8, %dx     # move the ascii byte to %dh
pushw %dx       # puch ascii code on the stack
inc %esp        # point to the ascii byte! (discard %dl)
inc %ecx        # count the digits
cmp $0, %eax
jnz loop

movl $4, %eax     # write()
movl $1, %ebx     # stdout
movl %ecx, %edx   # now edx holds the number of digits
movl %esp, %ecx   # load the address of string array
int $0x80         # the string array is on top of the stack

干杯！

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