计算外壳中文件的大小 [英] Calculate size of files in shell

问题描述

我试图仅使用Shell来计算与文件名模式匹配的所有文件(在目录树中)的总大小(以字节为单位).这是我到目前为止的内容:

I'm trying to calculate the total size in bytes of all files (in a directory tree) matching a filename pattern just using the shell. This is what I have so far:

查找-name * .undo -exec stat -c％s {} \; | awk'{total + = $ 1} END {print total}'

find -name *.undo -exec stat -c%s {} \; | awk '{total += $1} END {print total}'

有没有更简单的方法可以做到这一点?我觉得应该有一个简单的du或find开关可以为我完成此操作，但是我找不到.

Is there an easier way to do this? I feel like there should be a simple du or find switch that does this for me but I can't find one.

为了清楚起见，我想在目录树下的任何位置汇总与某个模式匹配的文件，这意味着

To be clear I want to total files matching a pattern anywhere under a directory tree which means

du -bs * .undo

du -bs *.undo

将不起作用，因为它仅与当前目录中的文件匹配.

won't work because it only matches the files in the current directory.

推荐答案

尝试:

find . -name "*.undo" -ls | awk '{total += $7} END {print total}'

在我的系统上，文件大小是find -ls输出中的第七个字段.如果您的find … -ls输出不同，请调整.

On my system the size of the file is the seventh field in the find -ls output. If your find … -ls output is different, adjust.

在此版本中，使用现有的目录信息(文件大小)和find的内置ls功能应该有效，避免创建进程或文件I/O.

In this version, using the existing directory information (file size) and the built-in ls feature of find should be efficient, avoiding process creations or file i/o.

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