如何请求文件，但不使用Wget保存文件? [英] How do I request a file but not save it with Wget?

问题描述

我正在使用Wget向新的Web服务器发出http请求.我这样做是为了预热MySQL缓存.提供文件后，我不想保存文件.

I'm using Wget to make http requests to a fresh web server. I am doing this to warm the MySQL cache. I do not want to save the files after they are served.

wget -nv -do-not-save-file $url

我可以用wget做类似-do-not-save-file的事情吗?

Can I do something like -do-not-save-file with wget?

推荐答案

将q标志用于安静模式，并告诉wget使用O-(大写o)输出到stdout并重定向到/dev/null放弃输出:

Use q flag for quiet mode, and tell wget to output to stdout with O- (uppercase o) and redirect to /dev/null to discard the output:

wget -qO- $url &> /dev/null

>将应用程序输出重定向到文件.如果>前面跟有&号，则Shell会将所有输出(错误和正常)重定向到>的文件权限.如果您未指定&"号，则仅重定向普通输出.

> redirects application output (to a file). if > is preceded by ampersand, shell redirects all outputs (error and normal) to the file right of >. If you don't specify ampersand, then only normal output is redirected.

./app &>  file # redirect error and standard output to file
./app >   file # redirect standard output to file
./app 2>  file # redirect error output to file

如果文件是/dev/null，则全部丢弃.

if file is /dev/null then all is discarded.

这也很好，也更简单:

wget -O/dev/null -q $url

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