如何在Linux bash/shell中对图像进行base64编码 [英] How to base64 encode image in linux bash / shell

问题描述

我正在尝试在shell脚本中对图像进行base64编码，然后将其放入变量中:

I'm trying to base64 encode an image in a shell script and put it into variable:

test="$(printf DSC_0251.JPG | base64)"
echo $test
RFNDXzAyNTEuSlBH

我也尝试过这样的事情:

I've also tried something like this:

test=\`echo -ne DSC_0251.JPG | base64\`

但仍然没有成功.

我想做这样的事情:

curl -v -X POST -d '{"image":$IMAGE_BASE64,"location":$LOCATION,"time_created":$TIMECREATED}' -H 'Content-type: text/plain; charset=UTF8' http://192.168.1.1/upload

我找到了这个 http ://www.zzzxo.com/q/answers-bash-base64-encode-script-not-encoding-right-12290484.html

但仍然没有成功.

推荐答案

您需要使用cat来获取名为'DSC_0251.JPG'的文件的内容，而不是文件名本身

You need to use cat to get the contents of the file named 'DSC_0251.JPG', rather than the filename itself.

test="$(cat DSC_0251.JPG | base64)"

但是，base64可以从文件本身读取:

However, base64 can read from the file itself:

test=$( base64 DSC_0251.JPG )

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