在目录和子目录中查找所有零字节文件 [英] Find all zero-byte files in directory and subdirectories

问题描述

如何在目录及其子目录中找到所有零字节文件?

How can I find all zero-byte files in a directory and its subdirectories?

我已经这样做了:

#!/bin/bash
lns=`vdir -R *.* $dir| awk '{print $8"\t"$5}'`
temp=""
for file in $lns; do
    if test $file = "0"; then
        printf $temp"\t"$file"\n"
    fi
    temp=$file
done

但是，我只在当前目录中获得结果，而不是子目录中的结果， 并且如果任何文件名包含空格，那么我只会得到第一个单词，后跟制表符

But, I only get results in the current directory, not subdirs, and if any file name contains a space then I get only first word followed by tab

推荐答案

要打印大小为$ 0的$ dir中及其以下的所有文件的名称:

To print the names of all files in and below $dir of size 0:

find "$dir" -size 0

请注意，并非所有find的实现都会默认生成输出，因此您可能需要这样做:

Note that not all implementations of find will produce output by default, so you may need to do:

find "$dir" -size 0 -print

关于问题的最后循环的两条评论:

Two comments on the final loop in the question:

除了遍历字符串中的每个其他单词并查看替代值是否为零外，您还可以通过遍历行来部分消除空白所带来的问题.例如:

Rather than iterating over every other word in a string and seeing if the alternate values are zero, you can partially eliminate the issue you're having with whitespace by iterating over lines. eg:

printf '1 f1\n0 f 2\n10 f3\n' | while read size path; do
    test "$size" -eq 0 && echo "$path"; done

请注意，如果ls输出的任何路径包含换行符，这将在您的情况下失败，并且这将加强两点:不要解析ls，并且具有明智的命名策略，该策略不允许在路径中使用空格

Note that this will fail in your case if any of the paths output by ls contain newlines, and this reinforces 2 points: don't parse ls, and have a sane naming policy that doesn't allow whitespace in paths.

第二，要从循环中输出数据，无需将输出存储在仅用于echo的变量中.如果仅让循环将其输出写入stdout，则可以完成相同的操作，但要避免存储它.

Secondly, to output the data from the loop, there is no need to store the output in a variable just to echo it. If you simply let the loop write its output to stdout, you accomplish the same thing but avoid storing it.

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