仅使用bash/标准Linux命令去除字符串中的单引号和双引号 [英] Stripping single and double quotes in a string using bash / standard Linux commands only

问题描述

我正在寻找仅使用bash/标准Linux命令就能将字符串转换为以下内容的东西:

I'm looking for something that will translate a string as follows, using only bash / standard Linux commands:

1. 应删除字符串中的单引号
2. 应删除字符串中的双引号
3. 未加引号的字符串应保持不变
4. 带有不匹配的引号的字符串应保持不变
5. 不包含字符串的单引号应保留
6. 不包含字符串的双引号应保留

例如:

• 食物"应成为食物
• 食物"应成为食物
• 食物应该保持不变
• 食物"应保持不变
• 食物"应保持不变
• 'Fo'od'应该成为Fo'od
• "Fo'od"应成为Fo'od
• 注意事项应该保持不变
• 'Fo'od'应该成为Fo'od
• "Fo" od应该变成Fo" od
• 焦点"应保持不变

• 'Food' should become Food
• "Food" should become Food
• Food should remain the same
• 'Food" should remain the same
• "Food' should remain the same
• 'Fo'od' should become Fo'od
• "Fo'od" should become Fo'od
• Fo'od should remain the same
• 'Fo"od' should become Fo"od
• "Fo"od" should become Fo"od
• Fo"od should remain the same

谢谢！

推荐答案

这应该做到:

sed "s/^\([\"']\)\(.*\)\1\$/\2/g" in.txt

in.txt在哪里:

Where in.txt is:

"Fo'od'
'Food'
"Food"
"Fo"od'
Food
'Food"
"Food'
'Fo'od'
"Fo'od"
Fo'od
'Fo"od'
"Fo"od"
Fo"od

expected.txt是:

And expected.txt is:

"Fo'od'
Food
Food
"Fo"od'
Food
'Food"
"Food'
Fo'od
Fo'od
Fo'od
Fo"od
Fo"od
Fo"od

您可以检查它们是否与以下项匹配:

You can check they match with:

diff -s <(sed "s/^\([\"']\)\(.*\)\1\$/\2/g" in.txt) expected.txt

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